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![limit n→∞pi/n [ sinpi/n+sin2pi/n+ .... +sin (n - 1 )pi/n ] is equal to :](https://haygot.s3.amazonaws.com/questions/1954614_1038211_ans_1fb8b3c433424f49823729fa116112f1.jpeg "limit n→∞pi/n [ sinpi/n+sin2pi/n+ .... +sin (n - 1 )pi/n ] is equal to :")
limit n→∞pi/n [ sinpi/n+sin2pi/n+ .... +sin (n - 1 )pi/n ] is equal to :
Solved F(t) = t, -pi less then are equal to t < pi f(t + 2 | Chegg.com
Infinite Series SUM(cos(n*pi)/(n + 1)) Calculus II Alternating Series Test Example - YouTube
sigma(n=1, infinity) (-1)^n * cos(pi/n) Test the series for convergence or divergence. - YouTube
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Pi Formulas -- from Wolfram MathWorld
![underset(nrarroo)"lim"[sin'(pi)/(n)+sin'(2pi)/(n)+"......"+sin'((n-1))/(n)pi] is equal to :](https://d10lpgp6xz60nq.cloudfront.net/ss/web/1423791.jpg "underset(nrarroo)\"lim\"[sin'(pi)/(n)+sin'(2pi)/(n)+\"......\"+sin'((n-1))/(n)pi] is equal to :")
underset(nrarroo)"lim"[sin'(pi)/(n)+sin'(2pi)/(n)+"......"+sin'((n-1))/(n)pi] is equal to :
Sum (1/pi)^n geometric series by comparison to geometric series formula 1/pi common ratio. - YouTube
Pi Formulas -- from Wolfram MathWorld
trigonometry - Why $\sin(n\pi) = 0$ and $\cos(n\pi)=(-1)^n$? - Mathematics Stack Exchange
Summation of Sin(pi/n) - YouTube
algebra precalculus - How $n\pi +(-1)^n \pi/6 = n\pi + \pi/6$ and $n\pi - (- 1)^n \pi/6 = n\pi - \pi/6$? - Mathematics Stack Exchange
Leibniz formula for π - Wikipedia
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Why was this reduced from 2(pi)(n) to (pi)(n)? From Paul's Online Notes, Calc 1, Section 1-6 Practice problems : r/askmath
